﻿ Glycolysis

Reactivity in Chemistry

Mechanisms of Glycolysis

GL11.  Solutions for Selected Problems.

ProblemGL1.1.

Bonds Broken:

C-C 6 x 80 kcal/mol = 480 kcal/mol

C-H 16 x 100 kcal/mol = 1,600 kcal/mol

O=O  7 x 120 kcal/mol = 840 kcal/mol

Total:  2,920 kcal/mol

C=O 14 x (- 190 kcal/mol) = - 2,660 kcal/mol

O-H 16 x (- 110 kcal/mol) = -1,760 kcal/mol

Total:  -4,420 kcal/mol

Overall:  1,240 - 4,420 kcal/mol = -1,500 kcal/mol

ProblemGL1.2.

Bonds Broken:

C-C 7 x 80 kcal/mol = 560 kcal/mol

C-H 18 x 100 kcal/mol = 1,800 kcal/mol

O=O  12.5 x 120 kcal/mol = 1,500 kcal/mol

Total:  3,860 kcal/mol

C=O 16 x (- 190 kcal/mol) = - 3,040 kcal/mol

O-H 18 x (- 110 kcal/mol) = -1,980 kcal/mol

Total:  -5,020 kcal/mol

Overall:  3,860 - 5,020 kcal/mol = -1,160 kcal/mol

ProblemGL1.3.

Bonds Broken:

C-C 6 x 80 kcal/mol = 480 kcal/mol

C-H 7 x 100 kcal/mol = 700 kcal/mol

C-O 7 x 85 kcal/mol = 595 kcal/mol

O-H 5 x 110 kcal/mol = 550 kcal/mol

O=O  6 x 120 kcal/mol = 840 kcal/mol

Total:  3,165 kcal/mol

C=O 12 x (- 190 kcal/mol) = - 2,280 kcal/mol

O-H 12 x (- 110 kcal/mol) = -1,320 kcal/mol

Total:  -3,600 kcal/mol

Overall:  3,165 - 3,600 kcal/mol = -435 kcal/mol

ProblemGL1.4.

Problem GL1.5.

In the mechanism for hydrolysis, water acts as a nucleophile and ATP acts as an electrophile.  That's a problem because ATP is negatively charged.  It will not attract electrons very easily.  By binding to magnesium ion (Mg2+), the charge on the ATP will be lowered, accelerating the reaction with water.

Problem GL2.1.

glucose  +  2 ATP   →    2 G3P  +  2 ADP

Problem GL2.2.

G3P  +     NAD+  +  PO43-   +  2 ADP    →     pyr   +   NADH   +   2 ATP   +  H2O

Problem GL2.3.

First we need to realise that one glucose gives rise to two molecules of G3P, so the second phase occurs twice for every glucose molecule consumed.

2 G3P  +     2  NAD+  +  2 PO43-   +  4 ADP    →   2  pyr   +   2 NADH   +   4 ATP   + 2  H2O

Adding the equations for the two phases together gives:

glucose   +   2 ATP   +  2 G3P  +    2 NAD+  +  2 PO43-   +  4 ADP    →   2 G3P  +  2 ADP  +  2  pyr   +   2 NADH   +   4 ATP   + 2  H2O

That equation can be simplified, because some things appear on both the left and the right.  It's just like algebra.

glucose    +    2 NAD+  +  2 PO43-   +  2 ADP    →      2  pyr   +   2 NADH   +   2 ATP   + 2  H2O

Problem GL2.4.

Problem GL2.5.

Problem GL2.6.

Problem GL2.7.

Problem GL2.8.

Problem GL3.1.

Problem GL3.2.

Problem GL3.3.

Problem GL3.4.

Problem GL3.5.

Problem GL3.6.

Problem GL4.1.

Problem GL4.2.

Problem GL4.3.

Problem GL4.4.

Problem GL4.5.

Problem GL5.1.

Problem GL5.2.

This site is written and maintained by Chris P. Schaller, Ph.D., College of Saint Benedict / Saint John's University.  These materials are available for educational use.

Send corrections to cschaller@csbsju.edu

This material is based upon work supported by the National Science Foundation under Grant No. 1043566.

Any opinions, findings, and conclusions or recommendations expressed in this material are those of the author(s) and do not necessarily reflect the views of the National Science Foundation.