Reactivity in Chemistry

Coordination Chemistry

CC5. Pi Coordination: Donation from Alkenes

Lone pairs are the most common electron donors in coordination complexes.  Chloride ions, ammonia and phosphines all donate a lone pair to metals to form complexes.  Lone pairs are not stabilized by bonding interactions already.  Forming a bond lowers the energy of the lone pair electrons.  On the other hand, bonding pairs are already lower in energy and so they are less likely to be donated.

However, pi bonds can also donate to Lewis acids.  Donation from sigma bonds is still much less likely, though.  Sigma bonds are buried between atoms and are hard to reach. 

A simple example of donation from a pi bond is the treatment of silver(I) salts with alkenes, shown in figure CC4.1.

Figure CC5.1.  Formation of a silver alkene complex or "silver olefin" complex.

Strictly speaking, if an alkene donates its pi bonding electrons to a metal, we might draw it as shown in Figure CC4.2.  The electrons are shared between two carbon atoms in the alkene.  Since a bond is generally thought of as a pair of electrons shared between two atoms, then once the pi electrons are donated to the metal, they are shared between the metal and one of the carbons, but not both.  If you are keeping track of electrons carefully, that leaves one of the carbons short on electrons.  It must be a cation.  Of course, either carbon could be the cationic one, so we can draw resonance structures showing both possible states.


Figure CC5.2.  Donation of a pair of pi-bonding electrons to a transition metal.

However, if a metal has valence electrons of its own, it could donate these electrons back to the "cation" that is forming on one of the alkene carbons.  The alkene complex can be thought of as a "metallacycle" or a "metallacyclopropane", a three-membered ring containing two carbons and the transition metal atom.


Figure CC5.3.  "Back-donation" of electrons from the metal to the alkene, in a Lewis sense.

The idea of back-donation is also supported from a molecular orbital point of view.  The alkene pi bond can donate electrons into an empty orbital on the metal, such as a p orbital.  In turn, an occupied metal d orbital has the correct symmetry to overlap with a pi* orbital on the alkene.  In doing so, we would think of the pi bond as breaking.  We would also think of two pairs of bonding electrons between the metal and alkenes.  This situation fits the picture of a metallacyle pretty well.

Figure CC5.4.   "Back-donation" of electrons from the metal to the alkene, in an MO sense.

Remember that formalisms can be complicated in coordination complexes.  For one thing, we do not usually draw positive formal charges on the donor atom or negative formal charges on the metal atom in the complex (unless specifically illustrating a point).  In alkene complexes, bonding is usually illustrated with a line between the pi bond and the metal, as in Figure CC4.5.  That line could be read as a pair of electrons, but it isn't, really.  The pair of electrons is in the pi bond.  They are being shared with the metal.


Figure CC5.5.   Typical representation of alkene complexes.



Problem CC5.1.

Alkene binding is one of the first steps performed by hydrogenation catalysts such as Wilkinson's catalyst, which catalyze the addition of dihydrogen across an alkene double bond to form an alkane.

Show, with arrows,  the coordination of cyclohexene to Wilkinson's catalyst, (PPh3)3RhCl.

Problem CC5.2.

The first example of an alkene coordinated to a transition metal was prepared by pharmaceutical chemist W. C. Ziese at the University of Copenhagen in 1827.  Its structure was confirmed by x-ray diffraction about a century later.  Its formula is K[PtCl3(CH2CH2)].  Draw the structure.

Problem CC5.3.

Crabtree's catalyst is a hydrogenation catalyst with formula [(COD)(py)(PCy3)Ir] PF6.  Note that COD = 1,4-cyclooctadiene; py = pyridine; Cy = cyclohexyl.  Draw the structure of this square planar iridium complex.

Problem CC5.4.

Treatment of alkenes with Hg(II) in water results in addition of a solvent molecule (a nucleophile) to one end of the "activated" alkene.  Draw, with arrows, the mechanism for the formation of a hydroxyethylmercury  ion, HgCH2CH2OH+, from ethene under these conditions.

Problem CC5.5.

Treatment of 2-methylpropene with Hg(II) in water results in formation of the  ion, HgCH2C(CH3)2OH+.  A second product of solvent addition is possible, but is not observed.  Show the other possible product and provide a possible explanation for the selectivity of the reaction.

Problem CC5.6.

Alkenes coordinate to many metals tightly enough that alkene complexes can be isolated and characterized.  However, although early metal ions such as Zr(IV) are believed to bind alkenes, they do not coordinate tightly enough to form stable compounds that can be isolated and characterized.  Explain why.

Problem CC5.7.

Alkynes can also coordinate to metal atoms.  Draw the molecular orbitals involved in:

a) alkyne donation to the metal

b) metal donation to the alkyne

Problem CC5.8.

Explain the differences seen in the equilibrium constants for the formation of silver(I) complexes with the following alkenes:

a) CH2CH2: K =  22.3  

b) cis-CH3CHCHCH2CH2CH3: K =   3.1   

c) trans-CH3CHCHCH2CH2CH3: K =  0.8


This site is written and maintained by Chris P. Schaller, Ph.D., College of Saint Benedict / Saint John's University (with contributions from other authors as noted).  It is freely available for educational use.

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This material is based upon work supported by the National Science Foundation under Grant No. 1043566.

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