Reactivity in Chemistry

Reaction Kinetics

MK9. Solutions to Selected Problems

Problem MK4.1.

a) non-competitive

b)  competitive

c)  competitive

d) non-competitive

Problem MK5.1.

a)  Vmax = 1.8 x 10-5 mol L-1 s-1

     Vmax / 2 = 9 x 10-6 mol L-1 s-1  so Km = 6 mol L-1   

b) Vmax = 6.5 x 10-7 mol L-1 s-1

     Vmax / 2 = 3.25 x 10-7 mol L-1 s-1  so Km = 7 mol L-1   

c)  Vmax = 2.6 x 10-5 mol L-1 s-1

     Vmax / 2 = 1.3 x 10-5 mol L-1 s-1  so Km = 6 mol L-1   

d)  Vmax = 1.2 x 10-5 mol L-1 s-1

     Vmax / 2 = 6 x 10-6 mol L-1 s-1  so Km = 6 mol L-1   

e)  Vmax = 6.0 x 10-7 mol L-1 s-1

     Vmax / 2 = 3 x 10-7 mol L-1 s-1  so Km = 13 mol L-1   

   

Problem MK5.2.

a)  1/Vmax = 30 L s mol-1 so Vmax = 3.3 x 10-2 mol L-1 s-1     

     -1/Km = -40 L mmol-1 so Km =  2.5 x 10-2 M L-1            

b)  1/Vmax = 50 L s mol-1 so Vmax = 2.0 x 10-2 mol L-1 s-1     

     -1/Km = -70 L mmol-1 so Km =  1.4 x 10-2 M L-1           

c)  1/Vmax = 60 L s mol-1 so Vmax = 1.7 x 10-2 mol L-1 s-1     

     -1/Km = -70 L mmol-1 so Km =  1.4 x 10-2 M L-1           

d)  1/Vmax = 50 L s mol-1 so Vmax = 2.0 x 10-2 mol L-1 s-1     

     -1/Km = -100 L mmol-1 so Km =  1.0 x 10-2 M L-1           

e)  1/Vmax = 30 L s mol-1 so Vmax = 3.3 x 10-2 mol L-1 s-1     

     -1/Km = -100 L mmol-1 so Km =  1.0 x 10-2 M L-1           

a)  1/Vmax = 30 L s mol-1 so Vmax = 3.3 x 10-2 mol L-1 s-1     

     -1/Km = -60 L mmol-1 so Km =  1.7 x 10-2 M L-1           

 

Problem MK5.3.

a)  uncompetitive

b)  mixed

c)  noncompetitive

d) competitive

e)  uncompetitive

f)  noncompetitive

g) competitive

 

 

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