Reactivity in Chemistry
NF6. Solutions for Selected Problems
a) 0 b) 3- c) 3- d) 3+ e) 5+
a) O2 b) NO2- c) 2 e-
a) S: 4 x 2- = 8- ; Fe: 2 x 2+ + 2 x 3+ = 10+ ; total = 2+
b) S: 4 x 2- = 8- ; Fe: 1 x 2+ + 2 x 3+ = 8+ ; total = 0
c) S: 2 x 2- = 4- ; Fe: 2+ + 3+ = 5+ ; total = 1+
d) As the Fe becomes more reduced, the N-N stretching frequency decreases. That's because the more electron density there is on the Fe, the more it is able to backbond to the N2 (N2 is a π acceptor).
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