Introduction to Cell & Molecular Biology (BIOL121) - Dr. S.G. Saupe (ssaupe@csbsju.edu); Biology Department, College of St. Benedict/St. John's University, Collegeville, MN 56321 |
Time to be "Corny" - A Genetics Exercise
Maize can either self-pollinate or cross-pollinate. Because the male and female flowers are separate, maize is an easy plant for breeders to study. Many mutants of maize are known. We will study two mutations that are visible in the grains.
One mutant has purple pigmented grains rather than the wild-type
yellow coloration. The other
mutant, has wrinkled kernels instead of the wild-type smooth kernels.
The purple pigmentation is caused by production of a pigment in the
aleurone layer of the grain. Wrinkled
kernels arise when the endosperm contains more sugar than starch.
I.
MONOHYBRID CROSS:
Wild-type plants have yellow-pigmented grains; mutant
individuals have purple grains. Consider a cross between a true-breeding
yellow parent and a true-breeding purple parent.
See Figure 1 or the ear of corn at your desk labeled P.
Q1. Since both parents were true-breeding, they must be
_____________
(homozygous or heterozygous).
Q2. If the yellow parent self-pollinated, what would you expect one
of its ears to look like?
At
your desk is an ear with F1 offspring (or see Fig 2) from a cross between a
true-breeding yellow and true-breeding purple plants. Record your observations:
Purple grains _________ Yellow
grains ____________
% Purple _____________ % Yellow ______________
Q3. Were the results of
this cross as you expected? Explain.
Q4. Which allele is
dominant? ______________ (purple or yellow)
Q5. What is the evidence to
support your conclusion?
Q6. The F1 offspring are:
______________ (homozygous/heterozygous)
Q7. Using the letter P,
write the genotype of the purple parent ______
Q8. Write the genotype of
the yellow parent _________
Q9. Write the genotype(s) of
the F1 offspring __________
Q10. Is the recessive
phenotype visible in the F1? _______
Assume
that one of the F1 grains is planted, grown to maturity and allowed to
self-pollinate. The resulting
ears will bear the F2 offspring.
Q11. Write the
genotypes for this cross: _____
x _____
Q12. What phenotype(s) do
you expect to appear in the F2 generation ______________________
Q13. What percentage of the
F2 do you expect to be purple? _______
Q14. What percentage of the
F2 do you expect to be yellow? _______
Q15. What ratio of purple :
yellow do you expect? ___ : ___
Examine
an F2 ear (or see Fig 3). Count
the number of yellow and purple grains on the F2 ear and record your data below. (If you have a ear, use tape to mark rows.
Do not unwrap the ear and handle it with care.
purple grains ______ yellow
grains ______
total grains (individual)
Q16.
What percent of the F2 were purple?
_______
Q17. What percent of the F2
were yellow? _______
Q18. What is the ratio of
purple : yellow? ___ : ___
Q19. Do your data (Q18)
support your predictions (Q15)? (Hint:
You will need to perform a chi square analysis)
x2
= _______
Q20. The genotype of the
yellow grains in the F2 generation is_______
Q21. The two possible
genotypes of the purple grains are: ________
and _________
To distinguish between the two possible genotypes in the purple-grained
F2's, a geneticist would conduct a test cross.
In a test cross, a homozygous recessive individual is crossed with an
individual showing the dominant phenotype.
Thus, in our case, a yellow plant (homozygous recessive) will be crossed
with a purple one.
Q22. If the purple plant is homozygous dominant, what
percent of the offspring from the test cross do you expect to be purple?
________
Q23. If the purple plant is heterozygous, what percent of the offspring
do you expect to be yellow? ______ purple?
_______ and thus, the ratio of purple : yellow offspring will be
___ : ___.
You
have been given an ear of corn (or see Fig 4) that has resulted from a test
cross between a yellow and a purple parent.
Q24. The
suspected genotypes of the parent for this cross are:
Count
the number of yellow and purple grains on the test cross ear.
Record your data below:
Purple grains ________ Yellow
grains __________ Total grains
__________
Q25. What percent of the grains were purple? _____
Q26. What percent of the grains were yellow? _____
Q27. The ratio of purple : yellow is
___ : ___.
Q28. Do your data (Q27)
support your predictions (Q23)? (Hint:
You will need to perform a chi square analysis)
x2 = _______
II.
DIHYBRID CROSS:
Now, we will consider a cross involving two traits, grain color (purple
or yellow) and seed shape (wrinkled or smooth).
Grains that contain high concentrations of starch are smooth and those
that contain mostly sugar will be wrinkled.
Assume that a cross is made between one two true-breeding plants,
one that has purple smooth grains and the other with yellow wrinkled grains.
All the F1's are purple smooth.
Q29. Which is allele is
dominant? _____________ recessive? ___________
Q30. The genotype of the
purple smooth parent is _____________. (Use
the letter S to refer to the seed shape trait.)
Q31. The genotype of the
yellow wrinkled parent is ___________.
Q32. The genotype of the
F1's is ____________________.
Q33. The F1 can produce
gametes with four possible genotypes. These are:
__________ _________
_________ _________
Assume
that a seed from the F1 is planted, grown to maturity, allowed to self pollinate
and the resultant F2 ears collected. One
of them is at your desk or see Fig. 5.
Q34. Write the genotype for
this cross ___________
x ___________
Q35. List the four possible
phenotypes that could result in the F2:
Phenotype |
Predicted |
Observed |
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%
Expected |
Ratio |
#
Individuals |
%
Total |
Ratio |
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Q36. What percent of the F2
do you expect for each phenotype? And,
what ratio of phenotypes do you expect? Complete
the table above.
Now,
count the F2 grains being careful to count them all and to not damage the ear.
Record your data in the table above.
Q37. Do your data
support your predictions (Q35-36)? Support
your answer with a chi square analysis.
x2=
______________
Q38. Are the genes for kernel color and kernel texture linked? Explain.
Last updated: July 14, 2009 � Copyright by SG Saupe