BIOCHEMISTRY - DR. JAKUBOWSKI
03/17/2008
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Learning Goals/Objectives for Chapter 6C: After class, laboratory, and this reading, students will be able to
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Given what you already know about protein structure, it should be easy to figure how to inhibit an enzyme. Since structure mediates function, anything that would significantly change the structure of an enzyme would inhibit the activity of the enzyme. Hence extremes of pH and high temperature, all of which can denature the enzyme, would inhibit the enzyme in a irreversible fashion, unless it could refold properly. Alternatively we could add a small molecule which interacts noncovalently with the enzyme to either change its conformation or directly prevent substrate binding. Finally, we could covalently modify certain side chains, that if they are essential to enzymatic activity, would irreversibly inhibit the enzyme.
COVALENT INHIBITION
We discussed previously the types of reagents that would chemically modify specific side chains that might be critical for enzymatic activity. For example, iodoacetamide might abolish enzyme activity if a Cys side chain is required for activity. These reagents will usually modify several side chains, however, and determining which is critical for binding or catalytic conversion of the substrate can be difficult. One way would be to protect the active site with a saturating quantities of a ligand which binds reversibly at the active site. Then the chemical modification can be performed at varying reaction times. The critical side chain would be protected from the chemical modification, but the extent of protection would depend on the Kd, concentration of the protecting ligand., and the length of the reaction.
TYPES OF NONCOVALENT INHIBITION
A. COMPETITIVE
Competitive inhibition occurs when substrate (S) and inhibitor (I) both bind to the same site on the
enzyme. In effect, they compete for the active site and bind in a mutually exclusive
fashion. This is illustrated in the mechanism at the top of the figure to the left, and
in the molecular cartoon beneath it. There is another type of inhibition that would give
the same kinetic data. If S and I bound to different sites, and S bound to E and
produced a conformational change in E such that I could not bind (and vice versa), then
the binding of S and I would be mutually exclusive. This is called allosteric competitive
inhibition. Inhibition studies are usually done at several fixed and non-saturating
concentrations of I and varying S concentrations. The key kinetic parameters to understand
are Vm and Km. Let us assume for ease of equation derivation that I binds reversibly, and
with rapid equilibrium to E, with a dissociation constant Kis. A look at the top
mechanism shows that even in the presence of I, as S increases to infinity, all E is
converted to ES. That is, there is no free E to which I could bind. Now remember that Vm=
kcatEo. Under these condition, ES = Eo; hence v = Vm.
Vm is not
changed. However, the apparent Km, Kmapp, will change. We can use LaChatelier's
principle to understand this. If I binds to E alone, and not ES, it will shift the
equilibrium of E + S <==> ES to the left, which would have the affect of increasing
the Km app (i.e. it would appear that the affinity of E and S has decreased.).
The double reciprocal plot (Lineweaver Burk plot) offers a great way to visualize the
inhibition. In the presence of I, Vm does not change, but Km appears to increase.
Therefore, 1/Km, the x-intercept on the plot will get smaller, and closer to 0. Therefore
the plots will consists of a series of lines, with the same y intercept (1/Vm), and
the x intecepts (-1/Km) closer and closer to the 0 as I increases. These intersecting plots are
the hallmark of competitive inhibition.
Note that in the first three inhibition models discussed in this section, the Lineweaver-Burk plots are linear in the presence and absence of inhibitor. This suggests that plots of v vs S in each case would be hyperbolic and conform to the usual form of the Michaelis Menton equation, each with potentially different apparent Vm and Km values.
An equation, shown in the diagram above, can be derived which shows the effect of the competitive inhibitor on the velocity of the reaction. The only change is that the Km term is multiplied by the factor 1+I/Kis. Hence Kmapp = Km(1+I/Kis). This shows that the apparent Km does increase as we predicted. Kis is the inhibitor dissociation constant in which the inhibitor affects the slope of the double reciprocal plot.
If the data was plotted as vo vs log S, the plots would be sigmoidal, as we saw for plots of ML vs log L in Chapter 5B. In the case of competitive inhibitor, the plot of vo vs log S in the presence of different fixed concentrations of inhibitor would consist of a series of sigmoidal curves, each with the same Vm, but with different apparent Km values (where Kmapp = Km(1+I/Kis), progressively shifted to the right. Enyzme kinetic data is rarely plotted this way, but simple binding data for the M + L < == > ML equilibrium, in the presence of different inhibitor concentrations is.
Reconsider our discussion of the simple binding equilibrium, M + L <==> ML. When we wished to know how much is bound, or the fractional saturation, as a function of the log L, we considered three examples.
These scenarios show that if L varies over 4 orders
of magnitude (0.01Kd < Kd < 100Kd), or, in log terms, from
-2 + log Kd < log Kd < 2 + log Kd), irrespective of the
magnitude of the Kd, that Y varies from approximately 0 - 1.
In other words, Y varies from 0-1 when L varies from log Kd by +2. Hence, plots of Y vs log L for a series of binding reactions of increasingly higher Kd (lower affinity) would reveal a series of identical sigmoidal curves shifted progressively to the right, as shown below.

The same would be true of vo vs S in the presence of different concentration of a competitive inhibitor, for initial flux, Jo vs ligand outside, in the presence of a competitive inhibitor, or ML vs L (or Y vs L) in the presence of a competitive inhibitor.
Now that you are more familiar with binding, flux, and enzyme kinetics curves, in the presence and absence of inhibitors, you should be able to apply the above analysis to inhibition curves where the binding, initial flux, or the initial velocity is plotted at varying competitive inhibitor concentration at different fixed concentration nonsaturating concentrations of ligand or substrate. Consider the activity of an enzyme. Lets say that at some reasonable concentration of substrate (not infinite), the enzyme is approximately 100% active. If a competitive inhibitor is added, the activity of the enzyme would drop until at saturating (infinite) I, no activity would remain. Graphs showing this are shown below.
Figure: Inhibition of Enzyme Activity - % Activity vs log [Inhibitor]

Java
Applet: Competitive
Inhibition I; Competitive
Inhibition II
B. UNCOMPETITIVE
Uncompetitive inhibition occurs when I binds only to ES and not
free E. One can hypothesize that on binding S, a conformational change in E occurs which presents a
binding site for I. Inhibition occurs since ESI can not form product. It is a
dead end complex which has only one fate, to return to ES. This is illustrated in the
mechanism at the top of the figure to the left, and in the molecular cartoon beneath it.
Let us assume for ease of equation derivation that I binds reversibly to ES with a
dissociation constant Kii. A look at the top mechanism shows that in the
presence of I, as S increases to infinity, not all of E is converted to ES. That is,
there is a finite amount of ESI, even at infinite S. Now remember that Vm = kcatEo
if and only if all E is in the form ES . Under these conditions, the apparent
Vm, Vmapp is less than the real Vm without inhibitor. In addition, the
apparent Km, Kmapp, will change. We can use LaChatelier's principle to
understand this. If I binds to ES alone, and not E, it will shift the
equilibrium of E + S
<==> ES to the right , which would have the affect of decreasing the Kmapp (i.e.
it would appear that the affinity of E and S has increased.). The double reciprocal plot
(Lineweaver Burk plot) offers a great way to visualize the inhibition. In the presence of
I, both Vm and Km decrease. Therefore, -1/Km, the x-intercept on the plot, will get more
negative, and 1/Vm will get more positive. It turns out that they change to the same
extent. Therefore the plots will consist of a series of parallel lines, which is the
hallmark of uncompetitive inhibition.
(note: the first mathematical equation in the left box should read
Kii)
An equation, shown in the diagram above, can be derived which shows the effect of the
uncompetitive inhibitor on the velocity of the reaction. The only change is that the S
term in the denominator is multiplied by the factor 1+I/Kii. We would like to rearrange
this equation to show how Km and Vm are affected by the inhibitor, not S, which obviously
isn't. Rearranging the equation as shown above shows that Kmapp = Km/(1+I/Kii)
and
Vmapp = Vm/(1+I/Kii). This shows that the apparent Km and Vm do decrease as we
predicted. Kii is the inhibitor dissociation constant
in which the inhibitor affects the intercept of the double
reciprocal plot. Note that if I is zero, Km and Vm are unchanged.
Java
Applet: Uncompetitive
Inhibition
C. NONCOMPETITIVE
Noncompetitive inhibition occurs when I binds to both E and ES. We will look
at only the special case in which the dissociation constants of I for E and ES are the
same. This is called noncompetiive inhibition. In the more general case, the Kd's are
different, and the inhibition is called mixed. Since inhibition occurs, we will
hypothesize that ESI can not form product. It is a dead end complex which has only
one fate, to return to ES or EI. This is illustrated in the mechanism at the top of the
figure to the left, and in the molecular cartoon beneath it. Let us assume for ease of
equation derivation that I binds reversibly to E with a dissociation constant of Kis
(as we denoted for competitive inhibition) and to ES with a dissociation constant Kii
(as we noted for uncompetitive inhibition). Assume for noncompetitive inhibition that
Kis = Kii. A look at the top mechanism shows that in the presence of I, as S increases to
infinity, not all of E is converted to ES. That is, there is a finite amount of ESI,
even at infinite S. Now remember that Vm = kcatEo if and only if all E is in
the form ES . Under these conditions, the apparent Vm, Vmapp is less
than the real Vm without inhibitor. In contrast, the apparent Km, Kmapp,
will not change since I binds to both E and ES with the same affinity, and hence will not
perturb that equilibrium, as deduced from LaChatelier's principle. The double reciprocal
plot (Lineweaver Burk plot) offers a great way to visualize the inhibition. In the
presence of I, just Vm will decrease. Therefore, -1/Km, the x-intercept will stay the
same, and 1/Vm will get more positive. Therefore the plots will consists of a series of
lines intersecting on the x axis, which is the hallmark of noncompetitive
inhibition. You
should be able to figure out how the plots would appear if Kis is different from Kii
(mixed inhibition).
An equation, shown in the diagram above can be derived which shows the effect of the
uncompetitive inhibitor on the velocity of the reaction. In the denominator, Km is
multiplied by 1+I/Kis, and S by 1+I/Kii. We would like to rearrange this equation to show
how Km and Vm are affected by the inhibitor, not S, which obviously isn't. Rearranging the
equation as shown above shows that Kmapp = Km(1+I/Kis)/(1+I/Kii) = Km when
Kis=Kii, and
Vmapp = Vm/(1+I/Kii). This shows that the Km is unchanged and Vm decreases as we
predicted. The plot shows a series of lines intersecting on the x axis. Both the slope and
the y intercept are changed, which are reflected in the names of the two dissociation
constants, Kis and Kii. Note that if I is zero, Kmapp = Km and Vmapp
= Vm.
Java
Applet: Noncompetitive
Inhibition
If you can apply LeChatilier's principle, you should be able to draw the Lineweaver-Burk plots for any scenario of inhibition or even the opposite case, enzyme activation!
AGONIST AND ANTAGONIST OF LIGAND BINDING TO RECEPTORS: AN EXTENSION
The analysis of competitive, uncompetitive and noncompetitive inhibitors of enzymes can now be extended to understand how the activity of membrane receptors are affected by the binding of drugs. When receptors bind their natural target ligands (hormones, neurotransmitters), a biological effect is elicited. This usually involves a shape change in the receptor, a transmembrane protein, which activates intracellular activities. The bound receptor usually does not directly express biological activity, but initiates a cascade of events which leads to expression of intracellular activity. In some cases, however, the occupied receptor actually expresses biological activity itself. For example, the bound receptor can acquire enzymatic activity, or become an active ion channel.
Drugs targeted to membrane receptors can have a variety of effects. They may elicit the same biological effects as the natural ligand. If so, they are called agonists. Conversely they may inhibit the biological activity of the receptor. If so they called antagonists
Agonist
An agonist is a mimetic of the natural ligand and produces a similar biological effect as the natural ligand when it binds to the receptor. It binds at the same binding site, and leads, in the absence of the natural ligand, to either a full or partial response. In the latter case, it is called a partial agonist. The figure below shows the action of ligand, agonist, and partial agonist.
There is another kind of agonist, given the bizzare name inverse agonist. This term only makes sense (to me) when applied to a receptor that has a basal (or constituitive) activity in the absence of a bound ligand. If either the natural ligand or an agonist binds to the receptor site, the basal activity is increased. If however, an inverse agonists binds, the activity is decreased. An example of an inverse agonist (which we will discuss later) is the binding of the drug Ro15-4513 to the GABA receptor, which also binds benzodiazepines such as valium. When occupied by its natural ligand, GABA, the protein receptor is "activated" to become a channel allowing the inward flow of Cl- into a neural cell, inhibiting neuron activation. Valium potentiates the effect of GABA, which is enhanced even further in the presence of ethanol. Ro15-4513 binds to the benzodiazepine site, which leads to the opposite effect of valium, the inhibition of the receptor bound activity - a chloride channel.
For our purposes, just concentrate on the agonist and partial agonist.
Figure: Agonist and Partial Agonists

Antagonists
As there name implies, antagonist inhibit the effects of the natural ligand (hormone, neurotransmitter), agonist, partial agonist, and even inverse agonists (which will not be mentioned again). We can think of them as inhibitors of receptor activity, much as we considered in the sections above inhibitors of enzyme activity. As such, there can be different types of antagonists. These include:
Figure: Antagonists: Competitive and Noncompetitive (Mixed)

INHIBITION BY TEMPERATURE CHANGE
From 0 to about 40-50o C, enzyme activity usually increases, as do the rates of most reactions in the absence of catalysts. (Remember the general rule of thumb that reaction velocities double for each increase of 10oC.). At higher temperatures, the activity decreases dramatically as the enzyme denatures.
Figure: Temperature and Enzyme Activity

INHIBITION BY PH CHANGE
pH has a marked effect on the velocity of enzyme-catalyzed reactions.
Figure: pH and Enzyme Activity

Think of all the things that pH changes might affect. It might
The easiest assumption is that certain side chains necessary for catalysis must be in the correct protonation state. Thus, some side chain, with an apparent pKa of around 6, must be deprotonated for optimal activity of trypsin which shows an increase in activity with the increase centered at pH 6. Which amino acid side chain would be a likely candidate?
See the following figure which shows how pH effects on enzyme kinetics can be modeled at the chemical and mathematical level.
Figure: Chemical equations showing the mechanism of pH effects on enzyme catalyzed reactions

Figure: Mathematic equations modeling pH effects on enzyme catalyzed reactions

Figure: Graphs of pH effects on enzyme catalyzed reactions

Mathcad: Effect of pH on enzyme catalysis (by Paul Krause, Chemistry Department, University of Central Arkansas.
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