 
BIOCHEMISTRY - DR. JAKUBOWSKI
06/12/2014
| Learning Goals/Objectives for Chapter 6C: After class and this reading, students will be able to 
 | 
Reversible noncompetitive inhibition occurs when I binds to both E and ES. We will look at only the special case in which the dissociation constants of I for E and ES are the same. This is called noncompetiive inhibition. It is quite rare as it would be difficult to imagine a large inhibitor which inhibits the turnover of bound substrate having no effect on binding of S to E. However covalent interaction of protons with both E and ES can lead to noncompetitive inhibition. In the more general case, the Kd's are different, and the inhibition is called mixed. Since inhibition occurs, we will hypothesize that ESI can not form product. It is a dead end complex which has only one fate, to return to ES or EI. This is illustrated in the chemical equations and in the molecular cartoon below.
	
Let us assume for ease of equation derivation that I binds reversibly to 
	E with a dissociation constant of Kis (as we denoted for competitive 
	inhibition) and to ES with a dissociation constant Kii (as we noted for 
	uncompetitive inhibition). Assume for noncompetitive inhibition that Kis = 
	Kii. A look at the top mechanism shows that in the presence of I, as S 
	increases to infinity, not all of E is converted to ES. That is, there is a 
	finite amount of ESI, even at infinite S. Now remember that Vm = kcatEo if 
	and only if all E is in the form ES . Under these conditions, the apparent 
	Vm, Vmapp is less than the real Vm without inhibitor. In contrast, the  
	apparent Km, Kmapp, will not change since I binds to both E and ES with the 
	same affinity, and hence will not perturb that equilibrium, as deduced from 
	LaChatelier's principle. The double reciprocal plot (Lineweaver Burk plot) 
	offers a great way to visualize the inhibition. In the presence of I, just 
	Vm will decrease. Therefore, -1/Km, the x-intercept will stay the same, and 
	1/Vm will get more positive. Therefore the plots will consists of a series 
	of lines intersecting on the x axis, which is the hallmark of noncompetitive 
	inhibition. You should be able to figure out how the plots would appear if 
	Kis is different from Kii (mixed inhibition).
An equation, 
	shown in the diagram above can be derived which shows the effect of the 
	noncompetitive inhibitor on the velocity of the reaction. In the 
	denominator, Km is multiplied by 1+I/Kis, and S by 1+I/Kii. We would like to 
	rearrange this equation to show how Km and Vm are affected by the inhibitor, 
	not S, which obviously isn't. Rearranging the equation as shown above shows 
	that Kmapp = Km(1+I/Kis)/(1+I/Kii) = Km when Kis=Kii, and Vmapp = Vm/(1+I/Kii).  
	This shows that the Km is unchanged and Vm decreases as we predicted. The 
	plot shows a series of lines intersecting on the x axis. Both the slope and 
	the y intercept are changed, which are reflected in the names of the two 
	dissociation constants, Kis and Kii. Note that if I is zero, Kmapp = Km and 
	Vmapp = Vm.  Sometimes the Kis and Kii inhibition dissociations 
	constants are referred to as Kc and Ku (competitive and uncompetitive 
	inhibition dissociation constants.
	
Mixed (and non-)competitive inhibition (as shown by mechanism above) differ from competitive and uncompetiive inhibition in that the inhibitor binding is not simply a dead end reaction in which the inhibitor can only dissociate in a single reverse step. In the above equilibrium, S can dissociate from ESI to form EI so the system may not be at equilibrium. With dead end steps, no flux of reactants occurs through the dead end complex so the equilibrium for the dead end step is not perturbed.
Other mechanisms can commonly give mixed inhibition. For example, the product released in a ping pong mechanism (discussed in the next chapter) can give mixed inhibition.
	
If P, acting as a product inhibitor, can bind to two different forms of the enzyme (E' and also E), it will act as an mixed inhibitor.
	
 Java 
	Applet: 
	
	Noncompetitive Inhibition
Java 
	Applet: 
	
	Noncompetitive Inhibition
	 4/26/13
4/26/13 Wolfram 
	Mathematica CDF Player - Mixed Inhibition v vs S curves; Kis and Kii called 
	Kc and Ku (start sliders at high values) (free 
	plugin required)
Wolfram 
	Mathematica CDF Player - Mixed Inhibition v vs S curves; Kis and Kii called 
	Kc and Ku (start sliders at high values) (free 
	plugin required)
		 Interactive SageMath 
	MIxed Inhibition
Interactive SageMath 
	MIxed Inhibition
	 4/26/13
4/26/13 Wolfram 
	Mathematica CDF Player - Lineweaver-Burk plots for Mixed Inhibition v vs S curves (start sliders at 
	high values) (free plugin 
	required). Note where the inhibited and inhibited curves intersect at 
	different values of Kis and Kii (in the graph termed Kc and Ku).  When 
	Kis = Kii, the inhibition is noncompetitive.
Wolfram 
	Mathematica CDF Player - Lineweaver-Burk plots for Mixed Inhibition v vs S curves (start sliders at 
	high values) (free plugin 
	required). Note where the inhibited and inhibited curves intersect at 
	different values of Kis and Kii (in the graph termed Kc and Ku).  When 
	Kis = Kii, the inhibition is noncompetitive.
		 Interactive SageMath 
		Mixed Inhibition (Red graph + 
		Inhibitor, Blue graph - Inhibitor,
		Green Axes
Interactive SageMath 
		Mixed Inhibition (Red graph + 
		Inhibitor, Blue graph - Inhibitor,
		Green Axes 
If you can apply LeChatilier's principle, you should be able to draw the Lineweaver-Burk plots for any scenario of inhibition or even the opposite case, enzyme activation!
Figure: Summary of Reversible Enzyme Inhibition
	
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